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shell实现FizzBuzzWhizz问题示例(拉勾网面试题)

时间:2024-3-2 15:29     作者:韩俊     分类: Linux


试题: https://www.jinshuju.net/f/EGQL3D

语言: Shell (Bash)
运行方式:
sh num-game.sh 数字1 数字2 数字3
如果不想使用传递数字的方式, 可以修改 num-game.sh 第 9 行, 将
NUM=$*
改为
NUM='数字1 数字2 数字3'
然后直接运行 sh num-game.sh 即可


#!/bin/bash

## Author : TaxKiz
## Email : taxkiz@gmail.com

export PATH='/bin:/sbin:/usr/bin:/usr/sbin'

## NUM='3 5 7'
NUM=$*

## 检查输入的数字个数是否为 3 个
function CT () {
[ $( echo $* | sed 's/ /n/g' | wc -l ) != '3' ] && echo " Please Enter 3 Number ! " && exit 1
}

CT $NUM

## 个位数列表
NT='1/2/3/4/5/6/7/8/9'

## 检查输入的数字是否为个位数
function CK () {
for num in $*
do
[ $num == '0' ] && echo "Error Number '$num'" && exit 2
echo $NT | grep "b$numb" > /dev/null 2>&1
[ $? != '0' ] && echo "$num is not a single digit" && exit 3
done
}

CK $NUM

## 判断是否有重复的数字
function SN () {
if [ $1 == $2 ] || [ $1 == $3 ] || [ $2 == $3 ]; then
echo "ERROR! There have same number : '$*'"
exit 4
fi
}

SN $NUM

## 大喊一声
function GO () {

A1=$1
A2=$2
A3=$3

T1=$(( $1 * $2 ))
T2=$(( $1 * $3 ))
T3=$(( $2 * $3 ))

TA=$(( $1 * $2 * $3 ))

for num in {1..100}
do
echo $num | grep $A1 > /dev/null 2>&1
[ $? == '0' ] && echo 'Fizz' && continue

echo "scale=2; $num/$TA" | bc | grep 00 > /dev/null 2>&1
[ $? == '0' ] && echo 'FizzBuzzWhizz' && continue

echo "scale=2; $num/$T1" | bc | grep 00 > /dev/null 2>&1
[ $? == '0' ] && echo 'FizzBuzz' && continue

echo "scale=2; $num/$T2" | bc | grep 00 > /dev/null 2>&1
[ $? == '0' ] && echo 'BuzzWhizz' && continue

echo "scale=2; $num/$T3" | bc | grep 00 > /dev/null 2>&1
[ $? == '0' ] && echo 'FizzWhizz' && continue

echo "scale=2; $num/$A1" | bc | grep 00 > /dev/null 2>&1
[ $? == '0' ] && echo 'Fizz' && continue

echo "scale=2; $num/$A2" | bc | grep 00 > /dev/null 2>&1
[ $? == '0' ] && echo 'Buzz' && continue

echo "scale=2; $num/$A3" | bc | grep 00 > /dev/null 2>&1
[ $? == '0' ] && echo 'Whizz' && continue

echo $num

done
}

GO $NUM

标签: linux

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