本文实例讲述了php实现不通过扩展名准确判断文件类型的方法。分享给大家供大家参考,具体如下:
第一种方法
通过php的finfo_file()
$handle=finfo_open(FILEINFO_MIME_TYPE);//This function opens a magic database and returns its resource. $fileInfo=finfo_file($handle,'./test.txt');// Return information about a file finfo_close($handle); print_r($fileInfo); echo '==========="n"';
另外
finfo_buffer: Return information about a string buffer
finfo_close: Close fileinfo resource
mime_content_type:Detect MIME Content-type for a file (deprecated)
第二种方法
通过二进制流获取文件内容
$fp=fopen('test.txt','r')///实际是image/png $bin = fread($fp, 2); //只读2字节 fclose($fp); $str_info = @unpack(“C2chars”, $bin);//Unpack data from binary string $type_code = intval($str_info['chars1'].$str_info['chars2']);// Get the integer value of a variable $file_type = ”; switch ($type_code) { case 7790: $file_type = 'exe'; break; case 7784: $file_type = 'midi'; break; case 8075: $file_type = 'zip'; break; case 8297: $file_type = 'rar'; break; case 255216: $file_type = 'jpg'; break; case 7173: $file_type = 'gif'; break; case 6677: $file_type = 'bmp'; break; case 13780: $file_type = 'png'; break; default: $file_type = 'unknown'; break; }
希望本文所述对大家PHP程序设计有所帮助。