本文实例讲述了php+html5+ajax实现上传图片的方法。分享给大家供大家参考，具体如下：
<?php
if (isset($_POST['upload'])) {
var_dump($_FILES);
move_uploaded_file($_FILES['upfile']['tmp_name'], 'up_tmp/'.time().'.dat');
//header('location: test.php');
exit;
}
?>
<!doctype html>
<html lang="zh">
<head>
<meta charset="utf-8">
<title>HTML5 Ajax Uploader</title>
<script src="jquery-2.1.1.min.js"></script>
</head>
<body>
<p><input type="file" id="upfile"></p>
<p><input type="button" id="upJS" value="用原生JS上传"></p>
<p><input type="button" id="upJQuery" value="用jQuery上传"></p>
<script>
/*原生JS版*/
document.getElementById("upJS").onclick = function() {
/* FormData 是表单数据类 */
var fd = new FormData();
var ajax = new XMLHttpRequest();
fd.append("upload", 1);
/* 把文件添加到表单里 */
fd.append("upfile", document.getElementById("upfile").files[0]);
ajax.open("post", "test.php", true);
ajax.onload = function () {
console.log(ajax.responseText);
};
ajax.send(fd);
}
/* jQuery 版 */
$('#upJQuery').on('click', function() {
var fd = new FormData();
fd.append("upload", 1);
fd.append("upfile", $("#upfile").get(0).files[0]);
$.ajax({
url: "test.php",
type: "POST",
processData: false,
contentType: false,
data: fd,
success: function(d) {
console.log(d);
}
});
});
</script>
</body>
</html>
希望本文所述对大家PHP程序设计有所帮助。